16a^2+56a+49=49

Solution for 16a^2+56a+49=49 equation:

16a^2+56a+49=49

We move all terms to the left:

16a^2+56a+49-(49)=0

We add all the numbers together, and all the variables

16a^2+56a=0

a = 16; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·16·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*16}=\frac{-112}{32}
=-3+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*16}=\frac{0}{32}
=0
$